(a^3-5a^2+7a)/a

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Solution for (a^3-5a^2+7a)/a equation: 


D( a )

a = 0

a = 0

a = 0

a in (-oo:0) U (0:+oo)

(a^3-(5*a^2)+7*a)/a = 0

(a^3-5*a^2+7*a)/a = 0

a^3-5*a^2+7*a = 0

a*(a^2-5*a+7) = 0

a^2-5*a+7 = 0

DELTA = (-5)^2-(1*4*7)

DELTA = -3

DELTA < 0

a = 0

1 = 0

a belongs to the empty set

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